Enumerative problem A14253A31254A14236XZ = 7 on Fl(1,2,3,4,5;6)

Experimental data Related Problems
Number of Real Solutions
  Necklaces     1     3     5     7  
  AabCB     0     0     48     1952  
  AaCbB     0     0     51     1949  
  AaBbC     0     0     1137     863  
  ABabC     0     0     1137     863  
  AabBC     0     107     1071     822  
  ABbaC     0     107     1071     822  
  AaBCb     0     127     1015     858  
  AbCaB     0     212     1157     631  
  AbaBC     0     882     823     295  
  AbBaC     0     882     823     295  
  AaCBb     60     153     803     984  
  AbaCB     81     143     784     992  
Projections
VarietyProblem#
Fl(2,4,5;6) (A13254)2A14253A14236Z
Fl(1,2,4,5;6) A13254A14253A31254A14236Z
Fl(2,3,4,5;6) A13254A14253A14236XZ
Key
Condition Name Symbol Codimension
 14253   A14253   A   3 
 31254   A31254   B   3 
 14236   A14236   C   3 
 13524   X   a   3 
 12456   Z   b   3 
Point Selection
Total time of computation: 115 423.13 GHz-seconds or 1.33 GHz-days on Rota
24 000 Polynomial systems solved
The coefficients of a typical eliminant had 50 digits.
The typical eliminant had size 438 bytes.
This table automatically generated from the data in This File using This Maple Script
Created: Fri Jul 15 15:38:49 CDT 2005